1965 AHSME Problems/Problem 18

Revision as of 23:51, 2 July 2017 by Skupp3 (talk | contribs) (Created page with "<math> \frac{1}{1 + y} = \frac{1 - y}{1 - y^2}</math> <math> \frac{1 - y}{\frac{1 - y}{1 - y^2}} = 1 - y^2</math> <math> \boxed{(B) y^2}</math>")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

$\frac{1}{1 + y} = \frac{1 - y}{1 - y^2}$

$\frac{1 - y}{\frac{1 - y}{1 - y^2}} = 1 - y^2$

$\boxed{(B) y^2}$