1965 AHSME Problems/Problem 18
Problem
If is used as an approximation to the value of , the ratio of the error made to the correct value is:
Solution
The error made in this approximation is , and the correct value is . Taking the ratio of these two values, we have:
Thus, our answer is
See Also
1965 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 17 |
Followed by Problem 19 | |
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