Difference between revisions of "1966 AHSME Problems/Problem 20"

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== Solution ==
 
== Solution ==
 
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<math>\fbox{C}</math>
  
 
== See also ==
 
== See also ==

Latest revision as of 02:30, 15 September 2014

Problem

The negation of the proposition "For all pairs of real numbers $a,b$, if $a=0$, then $ab=0$" is: There are real numbers $a,b$ such that

$\text{(A) } a\ne 0 \text{ and } ab\ne 0 \qquad \text{(B) } a\ne 0 \text{ and } ab=0  \qquad \text{(C) } a=0 \text{ and } ab\ne 0$

$\text{(D) } ab\ne 0 \text{ and } a\ne 0 \qquad \text{(E) } ab=0 \text{ and } a\ne 0$

Solution

$\fbox{C}$

See also

1966 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 19
Followed by
Problem 21
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