Difference between revisions of "1966 AHSME Problems/Problem 28"

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== Solution ==
 
== Solution ==
 
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<math>\fbox{B}</math>
  
 
== See also ==
 
== See also ==

Latest revision as of 02:33, 15 September 2014

Problem

Five points $O,A,B,C,D$ are taken in order on a straight line with distances $OA = a$, $OB = b$, $OC = c$, and $OD = d$. $P$ is a point on the line between $B$ and $C$ and such that $AP: PD = BP: PC$. Then $OP$ equals:

$\textbf{(A)} \frac {b^2 - bc}{a - b + c - d} \qquad \textbf{(B)} \frac {ac - bd}{a - b + c - d} \\  \textbf{(C)} - \frac {bd + ac}{a - b + c - d} \qquad \textbf{(D)} \frac {bc + ad}{a + b + c + d} \qquad \textbf{(E)} \frac {ac - bd}{a + b + c + d}$

Solution

$\fbox{B}$

See also

1966 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 27
Followed by
Problem 29
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