1966 AHSME Problems/Problem 39

Problem

In base $R_1$ the expanded fraction $F_1$ becomes $.373737\cdots$ , and the expanded fraction $F_2$ becomes $.737373\cdots$ . In base $R_2$ fraction $F_1$ , when expanded, becomes $.252525\cdots$ , while the fraction $F_2$ becomes $.525252\cdots$ . The sum of $R_1$ and $R_2$ , each written in the base ten, is:

$\text{(A) } 24 \quad \text{(B) } 22 \quad \text{(C) } 21 \quad \text{(D) } 20 \quad \text{(E) } 19$

Solution

$\fbox{E}$

1966 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 38	Followed by Problem 40
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

Page

Toolbox

Search

1966 AHSME Problems/Problem 39

Problem

Solution

See also