Difference between revisions of "1967 AHSME Problems/Problem 34"
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Revision as of 01:53, 23 September 2014
Problem
Points , , are taken respectively on sides , , and of triangle so that . The ratio of the area of triangle to that of triangle is:
Solution
See also
1967 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 33 |
Followed by Problem 35 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.