1977 AHSME Problems/Problem 3

Revision as of 11:25, 21 November 2016 by E power pi times i (talk | contribs) (Solution)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem 3

A man has $2.73 in pennies, nickels, dimes, quarters and half dollars. If he has an equal number of coins of each kind, then the total number of coins he has is

$\text{(A)}\ 3 \qquad  \text{(B)}\ 5 \qquad  \text{(C)}\ 9 \qquad  \text{(D)}\ 10 \qquad  \text{(E)}\ 15$


Solution by e_power_pi_times_i

Denote the number of pennies, nickels, dimes, quarters, and half-dollars by $x$. Then $x+5x+10x+25x+50x = 273$, and $x = 3$. The total amount of coins is $5x$, which is $\textbf{\text{(E)}}\ 15$.