Difference between revisions of "1978 IMO Problems/Problem 2"
(Created page with "yeet") |
|||
(One intermediate revision by the same user not shown) | |||
Line 1: | Line 1: | ||
− | + | ==Problem== | |
+ | We consider a fixed point <math>P</math> in the interior of a fixed sphere<math>.</math> We construct three segments <math>PA, PB,PC</math>, perpendicular two by two<math>,</math> with the vertexes <math>A, B, C</math> on the sphere<math>.</math> We consider the vertex <math>Q</math> which is opposite to <math>P</math> in the parallelepiped (with right angles) with <math>PA, PB, PC</math> as edges<math>.</math> Find the locus of the point <math>Q</math> when <math>A, B, C</math> take all the positions compatible with our problem. | ||
+ | |||
+ | ==Solution== | ||
+ | {{solution}} | ||
+ | |||
+ | == See Also == {{IMO box|year=1978|num-b=1|num-a=3}} | ||
+ | |||
+ | [[Category:3D Geometry Problems]] | ||
+ | [[Category:Olympiad Geometry Problems]] |
Latest revision as of 17:00, 29 January 2021
Problem
We consider a fixed point in the interior of a fixed sphere We construct three segments , perpendicular two by two with the vertexes on the sphere We consider the vertex which is opposite to in the parallelepiped (with right angles) with as edges Find the locus of the point when take all the positions compatible with our problem.
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See Also
1978 IMO (Problems) • Resources | ||
Preceded by Problem 1 |
1 • 2 • 3 • 4 • 5 • 6 | Followed by Problem 3 |
All IMO Problems and Solutions |