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1983 AHSME Problems/Problem 1

Revision as of 15:13, 28 June 2015 by MathAwesome123 (talk | contribs) (→‎Solution)

Problem

If $x \neq 0, \frac x{2} = y^2$ and $\frac{x}{4} = 4y$, then $x$ equals

$\textbf{(A)}\ 8\qquad \textbf{(B)}\ 16\qquad \textbf{(C)}\ 32\qquad \textbf{(D)}\ 64\qquad \textbf{(E)}\ 128$

Solution

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