1983 AHSME Problems/Problem 1
Problem
If and , then equals
Solution
From , we get . Plugging in the other equation, , so . Factoring, we get , so the solutions are and . Since , we also have , so . Hence .
See Also
1983 AHSME (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
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