Difference between revisions of "1987 AIME Problems/Problem 6"

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== Problem ==
 
== Problem ==
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Rectangle <math>\displaystyle ABCD</math> is divided into four parts of equal area by five segments as shown in the figure, where <math>\displaystyle XY = YB + BC + CZ = ZW = WD + DA + AX</math>, and <math>\displaystyle PQ</math> is parallel to <math>\displaystyle AB</math>.  Find the length of <math>\displaystyle AB</math> (in cm) if <math>\displaystyle BC = 19</math> cm and <math>\displaystyle PQ = 87</math> cm.
  
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[[Image:AIME_1987_Problem_6.png]]
 
== Solution ==
 
== Solution ==
  

Revision as of 00:47, 11 February 2007

Problem

Rectangle $\displaystyle ABCD$ is divided into four parts of equal area by five segments as shown in the figure, where $\displaystyle XY = YB + BC + CZ = ZW = WD + DA + AX$, and $\displaystyle PQ$ is parallel to $\displaystyle AB$. Find the length of $\displaystyle AB$ (in cm) if $\displaystyle BC = 19$ cm and $\displaystyle PQ = 87$ cm.

AIME 1987 Problem 6.png

Solution

See also

1987 AIME (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions