Difference between revisions of "1987 AJHSME Problems/Problem 1"
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<math>.4+.02+.006 = .400 + .020 + .006 = .426\rightarrow \boxed{\text{E}}</math> | <math>.4+.02+.006 = .400 + .020 + .006 = .426\rightarrow \boxed{\text{E}}</math> | ||
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==See Also== | ==See Also== | ||
Latest revision as of 17:04, 12 May 2023
Problem
Solution
See Also
| 1987 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
