# Difference between revisions of "1987 AJHSME Problems/Problem 2"

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<math>\frac{2}{25}=</math> | <math>\frac{2}{25}=</math> | ||

− | <math>\text{(A)}\ .008 \qquad \text{(B)}\ .08 \qquad \text{(C)}\ .8 \qquad \text{(D)} 1.25 \qquad \text{(E)}\ 12.5</math> | + | <math>\text{(A)}\ .008 \qquad \text{(B)}\ .08 \qquad \text{(C)}\ .8 \qquad \text{(D)}\ 1.25 \qquad \text{(E)}\ 12.5</math> |

==Solution== | ==Solution== | ||

− | <math>\frac{2}{25}=\frac{2\cdot 4}{25\cdot 4} = \frac{8}{100} = \boxed{ | + | <math>\frac{2}{25}=\frac{2\cdot 4}{25\cdot 4} = \frac{8}{100} = 0.08\rightarrow \boxed{\text{B}}</math> |

==See Also== | ==See Also== | ||

− | [[ | + | {{AJHSME box|year=1987|num-b=1|num-a=3}} |

+ | [[Category:Introductory Algebra Problems]] |