Difference between revisions of "1987 AJHSME Problems/Problem 6"
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Latest revision as of 23:52, 4 July 2013
Problem
The smallest product one could obtain by multiplying two numbers in the set 
is
Solution
To get the smallest possible product, we want to multiply the smallest negative number by the largest positive number. These are 
and 
, respectively, and their product is 
, which is 
See Also
| 1987 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
