# Difference between revisions of "1988 AIME Problems/Problem 2"

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Diophantient (talk | contribs) (Added the solution to an AIME problem) |
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== Solution == | == Solution == | ||

+ | We see that <math>f(11)=4</math> | ||

+ | <math>f(4)=16</math> | ||

+ | <math>f(16)=49</math> | ||

+ | <math>f(49)=169</math> | ||

+ | <math>f(169)=256</math> | ||

+ | <math>f(256)=169</math> | ||

+ | Note that this revolves between the two numbers. | ||

+ | <math>f_{1984}(169)=169</math> | ||

== See also == | == See also == |