Difference between revisions of "1988 AIME Problems/Problem 2"

m (See also)
(Added the solution to an AIME problem)
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== Solution ==
 
== Solution ==
 +
We see that <math>f(11)=4</math>
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<math>f(4)=16</math>
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<math>f(16)=49</math>
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<math>f(49)=169</math>
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<math>f(169)=256</math>
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<math>f(256)=169</math>
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Note that this revolves between the two numbers.
 +
<math>f_{1984}(169)=169</math>
  
 
== See also ==
 
== See also ==

Revision as of 12:52, 27 March 2007

Problem

Solution

We see that $f(11)=4$ $f(4)=16$ $f(16)=49$ $f(49)=169$ $f(169)=256$ $f(256)=169$ Note that this revolves between the two numbers. $f_{1984}(169)=169$

See also

1988 AIME (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions
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