Difference between revisions of "1991 AHSME Problems/Problem 30"
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For any set <math>S</math>, let <math>|S|</math> denote the number of elements in <math>S</math>, and let <math>n(S)</math> be the number of subsets of <math>S</math>, including the empty set and the set <math>S</math> itself. If <math>A</math>, <math>B</math>, and <math>C</math> are sets for which <math>n(A)+n(B)+n(C)=n(A\cup B\cup C)</math> and <math>|A|=|B|=100</math>, then what is the minimum possible value of <math>|A\cap B\cap C|</math>? | For any set <math>S</math>, let <math>|S|</math> denote the number of elements in <math>S</math>, and let <math>n(S)</math> be the number of subsets of <math>S</math>, including the empty set and the set <math>S</math> itself. If <math>A</math>, <math>B</math>, and <math>C</math> are sets for which <math>n(A)+n(B)+n(C)=n(A\cup B\cup C)</math> and <math>|A|=|B|=100</math>, then what is the minimum possible value of <math>|A\cap B\cap C|</math>? | ||
− | (A) 96 (B) 97 (C) 98 (D) 99 (E) 100 | + | <math>(A) 96 \ (B) 97 \ (C) 98 \ (D) 99 \ (E) 100</math> |
== Solution == | == Solution == | ||
− | <math>\fbox{B}</math> | + | <math>n(A)=n(B)=2^{100}</math>, so <math>n(C)</math> and <math>n(A \cup B \cup C)</math> are integral powers of <math>2</math> <math>\Longrightarrow</math> <math>n(C)=2^{101}</math> and <math>n(A \cup B \cup C)=2^{102}</math>. Let <math>A=\{s_1,s_2,s_3,...,s_{100}\}</math>, <math>B=\{s_3,s_4,s_5,...,s_{102}\}</math>, and <math>C=\{s_1,s_2,s_3,...,s_{k-2},s_{k-1},s_{k+1},s_{k+2},...,s_{100},s_{101},s_{102}\}</math> where <math>s_k \in A \cap B</math> |
+ | Thus, the minimum value of <math>|A\cap B \cap C|</math> is <math>\fbox{B=97}</math> | ||
== See also == | == See also == |
Revision as of 15:18, 13 February 2018
Problem
For any set , let denote the number of elements in , and let be the number of subsets of , including the empty set and the set itself. If , , and are sets for which and , then what is the minimum possible value of ?
Solution
, so and are integral powers of and . Let , , and where Thus, the minimum value of is
See also
1991 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 29 |
Followed by Problem 30 | |
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All AHSME Problems and Solutions |
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