Difference between revisions of "1992 AIME Problems/Problem 14"

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== Problem ==
 
== Problem ==
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In triangle <math>ABC^{}_{}</math>, <math>\displaystyle A'</math>, <math>\displaystyle B'</math>, and <math>\displaystyle C'</math> are on the sides <math>\displaystyle BC</math>, <math>AC^{}_{}</math>, and <math>AB^{}_{}</math>, respectively. Given that <math>\displaystyle AA'</math>, <math>\displaystyle BB'</math>, and <math>\displaystyle CC'</math> are concurrent at the point <math>O^{}_{}</math>, and that <math>\frac{AO^{}_{}}{OA'}+\frac{BO}{OB'}+\frac{CO}{OC'}=92</math>, find <math>\frac{AO}{OA'}\cdot \frac{BO}{OB'}\cdot \frac{CO}{OC'}</math>.
  
 
== Solution ==
 
== Solution ==

Revision as of 22:45, 10 March 2007

Problem

In triangle $ABC^{}_{}$, $\displaystyle A'$, $\displaystyle B'$, and $\displaystyle C'$ are on the sides $\displaystyle BC$, $AC^{}_{}$, and $AB^{}_{}$, respectively. Given that $\displaystyle AA'$, $\displaystyle BB'$, and $\displaystyle CC'$ are concurrent at the point $O^{}_{}$, and that $\frac{AO^{}_{}}{OA'}+\frac{BO}{OB'}+\frac{CO}{OC'}=92$, find $\frac{AO}{OA'}\cdot \frac{BO}{OB'}\cdot \frac{CO}{OC'}$.

Solution

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See also