Difference between revisions of "1993 AHSME Problems/Problem 9"
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== Solution == | == Solution == | ||
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− | <math>\frac{ | + | Let <math>W</math> be the wealth of the world and <math>P</math> be the population of the world. Hence the wealth of each citizen of <math>A</math> is <math>w_A = \frac{0.01d W}{0.01cP}=\frac{dW}{cP}</math>. Similarly the wealth of each citizen of <math>B</math> is <math>w_B =\frac{eW}{fP}</math>. We divide <math>\frac{w_A}{w_B} = \frac{de}{cf}</math> and see the answer is <math>\fbox{D}</math> |
− | <math>\fbox{D}</math> | ||
== See also == | == See also == |
Latest revision as of 21:59, 27 May 2021
Problem
Country has of the world's population and of the worlds wealth. Country has of the world's population and of its wealth. Assume that the citizens of share the wealth of equally,and assume that those of share the wealth of equally. Find the ratio of the wealth of a citizen of to the wealth of a citizen of .
Solution
Let be the wealth of the world and be the population of the world. Hence the wealth of each citizen of is . Similarly the wealth of each citizen of is . We divide and see the answer is
See also
1993 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
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All AHSME Problems and Solutions |
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