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1998 AHSME Problems/Problem 5

Revision as of 16:08, 19 November 2009 by Lord.of.AMC (talk | contribs) (Created page with '<math>2^{1998} - 2^{1997} - 2^{1996} = 2^{1996}.</math> <math>2^{1996} + 2^{1995} = 2^{1995}(2 + 1) = 3 \cdot 2^{1995}.</math> So, the answer is <math>\text{(C)}.</math>')
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$2^{1998} - 2^{1997} - 2^{1996} = 2^{1996}.$ $2^{1996} + 2^{1995} = 2^{1995}(2 + 1) = 3 \cdot 2^{1995}.$ So, the answer is $\text{(C)}.$

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