Difference between revisions of "1998 IMO Problems/Problem 1"

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==Problem==
 
==Problem==
  
In the convex quadrilateral ABCD, the diagonals AC and BD are perpendicular
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In the convex quadrilateral <math>ABCD</math>, the diagonals <math>AC</math> and <math>BD</math> are perpendicular and the opposite sides <math>AB</math> and <math>DC</math> are not parallel. Suppose that the point <math>P</math>, where the perpendicular bisectors of <math>AB</math> and <math>DC</math> meet, is inside <math>ABCD</math>. Prove that <math>ABCD</math> is a cyclic quadrilateral if and only if the triangles <math>ABP</math> and <math>CDP</math> have equal areas.
and the opposite sides AB and DC are not parallel. Suppose that the point P ,
 
where the perpendicular bisectors of AB and DC meet, is inside ABCD. Prove
 
that ABCD is a cyclic quadrilateral if and only if the triangles ABP and CDP
 
have equal areas.
 
  
 
==Solution==
 
==Solution==
 
{{solution}}
 
{{solution}}
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==See Also==
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{{IMO box|year=1998|before=First Question|num-a=2}}

Latest revision as of 23:53, 18 November 2023

Problem

In the convex quadrilateral $ABCD$, the diagonals $AC$ and $BD$ are perpendicular and the opposite sides $AB$ and $DC$ are not parallel. Suppose that the point $P$, where the perpendicular bisectors of $AB$ and $DC$ meet, is inside $ABCD$. Prove that $ABCD$ is a cyclic quadrilateral if and only if the triangles $ABP$ and $CDP$ have equal areas.

Solution

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See Also

1998 IMO (Problems) • Resources
Preceded by
First Question
1 2 3 4 5 6 Followed by
Problem 2
All IMO Problems and Solutions