Difference between revisions of "1998 IMO Problems/Problem 1"
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− | In the convex quadrilateral ABCD, the diagonals AC and BD are perpendicular | + | ==Problem== |
− | and the opposite sides AB and DC are not parallel. Suppose that the point P , | + | |
− | where the perpendicular bisectors of AB and DC meet, is inside ABCD. Prove | + | In the convex quadrilateral <math>ABCD</math>, the diagonals <math>AC</math> and <math>BD</math> are perpendicular and the opposite sides <math>AB</math> and <math>DC</math> are not parallel. Suppose that the point <math>P</math>, where the perpendicular bisectors of <math>AB</math> and <math>DC</math> meet, is inside <math>ABCD</math>. Prove that <math>ABCD</math> is a cyclic quadrilateral if and only if the triangles <math>ABP</math> and <math>CDP</math> have equal areas. |
− | that ABCD is a cyclic quadrilateral if and only if the triangles ABP and CDP | + | |
− | have equal areas. | + | ==Solution== |
+ | {{solution}} | ||
+ | |||
+ | ==See Also== | ||
+ | |||
+ | {{IMO box|year=1998|before=First Question|num-a=2}} |
Latest revision as of 23:53, 18 November 2023
Problem
In the convex quadrilateral , the diagonals and are perpendicular and the opposite sides and are not parallel. Suppose that the point , where the perpendicular bisectors of and meet, is inside . Prove that is a cyclic quadrilateral if and only if the triangles and have equal areas.
Solution
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See Also
1998 IMO (Problems) • Resources | ||
Preceded by First Question |
1 • 2 • 3 • 4 • 5 • 6 | Followed by Problem 2 |
All IMO Problems and Solutions |