Difference between revisions of "1999 AHSME Problems/Problem 4"

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'''(D) 187'''
 
'''(E) 245'''
 
'''(E) 245'''
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==See Also==
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{{AHSME box|year=1999|num-b=3|num-a=5}}

Revision as of 13:49, 8 June 2011

Find the sum of all prime numbers between 1 and 100 that are simultaneously 1 greater than a multiple of 4 and 1 less than a multiple of 5. (A) 118 (B) 137 (C) 158 (D) 187 (E) 245

See Also

1999 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
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