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1999 AMC 8 Problems/Problem 5

Revision as of 21:26, 16 June 2011 by Kingofmath101 (talk | contribs) (Created page with "The perimeter of the rectangle is <math>50(2) + 10(2) = 100 + 20 = 120</math> feet. This fence is used for a square, which has four sides, so each side is <math>30</math> feet lo...")
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The perimeter of the rectangle is $50(2) + 10(2) = 100 + 20 = 120$ feet. This fence is used for a square, which has four sides, so each side is $30$ feet long.

Now to compare areas. The area of the rectangle is $(50)(10)$, or $500$ square feet. The square's area is $30^2$ square feet, or $900$ square feet. Subtracting the rectangular area from the square area, we have an increase of $400$ square feet.

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