Difference between revisions of "2000 AMC 10 Problems/Problem 10"

(New page: The largest possible value for <math>x</math> is <math>9</math>. The smallest is <math>3</math>. <math>9-3=6</math>. <math>8</math> is the smallest that cannot be made (of the choices li...)
 
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==Problem==
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==Solution==
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The largest possible value for <math>x</math> is <math>9</math>. The smallest is <math>3</math>.
 
The largest possible value for <math>x</math> is <math>9</math>. The smallest is <math>3</math>.
  
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<math>8</math> is the smallest that cannot be made (of the choices listed)
 
<math>8</math> is the smallest that cannot be made (of the choices listed)
  
D.
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<math>\boxed{\text{D}}</math>
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==See Also==
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{{AMC10 box|year=2000|num-b=9|num-a=11}}

Revision as of 19:38, 8 January 2009

Problem

Solution

The largest possible value for $x$ is $9$. The smallest is $3$.

$9-3=6$.

$8$ is the smallest that cannot be made (of the choices listed)

$\boxed{\text{D}}$

See Also

2000 AMC 10 (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions
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