Difference between revisions of "2000 AMC 10 Problems/Problem 10"
5849206328x (talk | contribs) m |
5849206328x (talk | contribs) (→Problem) |
||
Line 1: | Line 1: | ||
==Problem== | ==Problem== | ||
+ | |||
+ | The sides of a triangle with positive area have lengths <math>4</math>, <math>6</math>, and <math>x</math>. The sides of a second triangle with positive area have lengths <math>4</math>, <math>6</math>, and <math>y</math>. What is the smallest positive number that is '''not''' a possible value of <math>|x-y|</math>? | ||
+ | |||
+ | <math>\mathrm{(A)}\ 2 \qquad\mathrm{(B)}\ 4 \qquad\mathrm{(C)}\ 6 \qquad\mathrm{(D)}\ 8 \qquad\mathrm{(E)}\ 10</math> | ||
==Solution== | ==Solution== |
Revision as of 22:52, 8 January 2009
Problem
The sides of a triangle with positive area have lengths , , and . The sides of a second triangle with positive area have lengths , , and . What is the smallest positive number that is not a possible value of ?
Solution
The largest possible value for is . The smallest is .
.
is the smallest that cannot be made (of the choices listed)
See Also
2000 AMC 10 (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |