2000 AMC 10 Problems/Problem 13

Problem

The question is rather ambiguous, however I will assume that the pegs of the same color are distinguishable.

Clearly, there is only 1 possible ordering if the colors are indistinguishable.

Thus, $5! \cdot 4! \cdot 3! \cdot 2! \cdot 1!$

Or, C.

2000 AMC 10 (Problems • Answer Key • Resources)
Preceded by Problem 12	Followed by Problem 14
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