Difference between revisions of "2000 AMC 10 Problems/Problem 2"

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==See Also==
  
 
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{{AMC10 box|year=2000|before=First question|num-a=2}}

Revision as of 18:38, 8 January 2009

Problem

$2000\left(2000^{2000}\right)=$

$\mathrm{(A)}\ {2000}^{2001} \qquad \mathrm{(B)}\ {4000}^{2000} \qquad \mathrm{(C)}\ {2000}^{4000} \qquad \mathrm{(D)}\ {4,000,000}^{2000} \qquad\mathrm{(E)}\ {2000}^{4,000,000}$

Solution

$2000 \cdot 2000^{2000}=2000^1 \cdot 2000^{2000}=2000^{2000+1}=2000^{2001}$.

$\boxed{\text{A}}$

See Also

2000 AMC 10 (ProblemsAnswer KeyResources)
Preceded by
First question
Followed by
Problem 2
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All AMC 10 Problems and Solutions