Difference between revisions of "2000 AMC 10 Problems/Problem 8"
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==Problem== | ==Problem== | ||
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| + | At Olympic High School, <math>\frac{2}{5}</math> of the freshmen and <math>\frac{4}{5}</math> of the sophomores took the AMC-10. Given that the number of freshmen and sophomore contestants was the same, which of the following must be true? | ||
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| + | <math>\mathrm{(A)}</math> There are five times as many sophomores as freshmen. | ||
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| + | <math>\mathrm{(B)}</math> There are twice as many sophomores as freshmen. | ||
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| + | <math>\mathrm{(C)}</math> There are as many freshmen as sophomores. | ||
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| + | <math>\mathrm{(D)}</math> There are twice as many freshmen as sophomores. | ||
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| + | <math>\mathrm{(E)}</math> There are five times as many freshmen as sophomores. | ||
==Solution== | ==Solution== | ||
Revision as of 22:48, 8 January 2009
Problem
At Olympic High School, 
of the freshmen and 
of the sophomores took the AMC-10. Given that the number of freshmen and sophomore contestants was the same, which of the following must be true?
There are five times as many sophomores as freshmen.
There are twice as many sophomores as freshmen.
There are as many freshmen as sophomores.
There are twice as many freshmen as sophomores.
There are five times as many freshmen as sophomores.
Solution
Let 
be the number of freshman and s be the number of sophomores.
There are twice as many freshman as sophomores.
See Also
| 2000 AMC 10 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
