Difference between revisions of "2000 AMC 10 Problems/Problem 9"

Revision as of 19:36, 8 January 2009

$|x-2|=p$

$x<2$ , so $2-x=p$ .

$x+p=2$ .

$x-p=2-2p$ .

$\boxed{\text{C}}$

2000 AMC 10 (Problems • Answer Key • Resources)
Preceded by Problem 8	Followed by Problem 10
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 10 Problems and Solutions

@@ Line 12: / Line 12: @@
 <math>\boxed{\text{C}}</math>
+==See Also==
+{{AMC10 box|year=2000|num-b=8|num-a=10}}