Difference between revisions of "2000 AMC 8 Problems/Problem 8"
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Revision as of 10:24, 15 May 2011
Contents
Problem
Three dice with faces numbered through are stacked as shown. Seven of the eighteen faces are visible, leaving eleven faces hidden (back, bottom, between). The total number of dots NOT visible in this view is
Solution
Solution 1
The numbers on one die total , so the numbers on the three dice total . Numbers are visible, and these total . This leaves $63 - 22 = \boxed{{\text{(B) 41}} not seen.