Difference between revisions of "2001 IMO Problems/Problem 3"

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==Solution==
 
==Solution==
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Since there is a common problem that was solved by a pair of a girl and a boy, each person solved at least one problem. Now we prove that three boys will solve a problem that one of the girls gets.
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Let's say that a girl solved only one problem. Then all 21 boys will have solved that problem.
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Now we assume that a girl got two problems. Therefore, each boy must solve at least one of those problems. From the [[pigeonhole principle]], at least <math>\lfloor \frac{21}{2} \rfloor</math> boys must have solved one of those problems.
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We give a similar argument for three, four, five, and six problems.
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Therefore, at least three boys will solve a problem that one of the girls gets.
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{{solution}}
 
{{solution}}
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{{IMO box|year=2001|num-b=2|num-a=4}}
 
{{IMO box|year=2001|num-b=2|num-a=4}}
  
 
[[Category:Olympiad Combinatorics Problems]]
 
[[Category:Olympiad Combinatorics Problems]]

Revision as of 21:28, 27 October 2007

Problem

Twenty-one girls and twenty-one boys took part in a mathematical competition. It turned out that each contestant solved at most six problems, and for each pair of a girl and a boy, there was at least one problem that was solved by both the girl and the boy. Show that there is a problem that was solved by at least three girls and at least three boys.

Solution

Since there is a common problem that was solved by a pair of a girl and a boy, each person solved at least one problem. Now we prove that three boys will solve a problem that one of the girls gets.

Let's say that a girl solved only one problem. Then all 21 boys will have solved that problem.

Now we assume that a girl got two problems. Therefore, each boy must solve at least one of those problems. From the pigeonhole principle, at least $\lfloor \frac{21}{2} \rfloor$ boys must have solved one of those problems.

We give a similar argument for three, four, five, and six problems.

Therefore, at least three boys will solve a problem that one of the girls gets.

This problem needs a solution. If you have a solution for it, please help us out by adding it.


2001 IMO (Problems) • Resources
Preceded by
Problem 2
1 2 3 4 5 6 Followed by
Problem 4
All IMO Problems and Solutions