Difference between revisions of "2002 AIME I Problems/Problem 6"

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== Problem ==
 
== Problem ==
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The solutions to the system of equations
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<cmath>\log_{225}x+\log_{64}y=4</cmath>
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<cmath>\log_{x}225-\log_{y}64=1</cmath>
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are <math>(x_1,y_1)</math> and <math>(x_2,y_2)</math>. Find <math>\log_{30}\left(x_1y_1x_2y_2\right)</math>
  
 
== Solution ==
 
== Solution ==

Revision as of 16:31, 25 September 2007

Problem

The solutions to the system of equations

\[\log_{225}x+\log_{64}y=4\]

\[\log_{x}225-\log_{y}64=1\]

are $(x_1,y_1)$ and $(x_2,y_2)$. Find $\log_{30}\left(x_1y_1x_2y_2\right)$

Solution

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See also