Difference between revisions of "2003 AMC 10B Problems/Problem 1"

(AMC 10 B 2003- Problem 1)
 
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1.  Which of the following is the same as
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==Problem==
  
<math>\frac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}</math>?
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Which of the following is the same as <math>\dfrac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}</math>?
  
 
<math>\textbf{(A)}\ -1 \qquad
 
<math>\textbf{(A)}\ -1 \qquad
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\textbf{(D)}\ 1 \qquad
 
\textbf{(D)}\ 1 \qquad
 
\textbf{(E)}\ \frac{14}{3}</math>
 
\textbf{(E)}\ \frac{14}{3}</math>
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==Solution==
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{{solution}}
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==See Also==
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{{AMC10 box|year=2003|ab=B|before=First Question|num-a=2}}
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[[Category: Introductory Algebra Problems]]

Revision as of 16:39, 2 March 2011

Problem

Which of the following is the same as $\dfrac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}$?

$\textbf{(A)}\ -1 \qquad \textbf{(B)}\ -\frac23 \qquad \textbf{(C)}\ \frac23 \qquad \textbf{(D)}\ 1 \qquad \textbf{(E)}\ \frac{14}{3}$

Solution

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See Also

2003 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
First Question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions