Difference between revisions of "2005 Canadian MO Problems/Problem 4"

Revision as of 12:12, 8 October 2007

Let $ABC$ be a triangle with circumradius $R$ , perimeter $P$ and area $K$ . Determine the maximum value of $KP/R^3$ .

Since equilateral triangles are awesome, we try an equilateral triangle first:

$\dfrac{KP}{R^3}=\dfrac{27}{4}$

now we just need to prove that that is the maximum.

This problem needs a solution. If you have a solution for it, please help us out by adding it.

@@ Line 4: / Line 4: @@
 ==Solution==
+Since equilateral triangles are awesome, we try an equilateral triangle first:
+<math>\dfrac{KP}{R^3}=\dfrac{27}{4}</math>
+now we just need to prove that that is the maximum.
 {{solution}}

2005 Canadian MO (Problems)
Preceded by Problem 3	1 • 2 • 3 • 4 • 5	Followed by Problem 5