Difference between revisions of "2006 AMC 10B Problems/Problem 2"
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Since <math> x \spadesuit y = (x+y)(x-y) </math>: | Since <math> x \spadesuit y = (x+y)(x-y) </math>: | ||
− | <math> 3 \spadesuit (4 \spadesuit 5) = 3 \spadesuit((4+5)(4-5)) = 3 \spadesuit (-9) = (3+(-9))(3-(-9)) = -72 \Rightarrow A</math> | + | <math> 3 \spadesuit (4 \spadesuit 5) = 3 \spadesuit((4+5)(4-5)) = 3 \spadesuit (-9) = (3+(-9))(3-(-9)) = -72 \Rightarrow \boxed{A}</math> |
== See Also == | == See Also == |
Latest revision as of 13:52, 12 June 2020
Problem
For real numbers and , define . What is ?
Solution
Since :
See Also
2006 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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