Difference between revisions of "2006 AMC 8 Problems/Problem 9"
Math Kirby (talk | contribs) (Created page with "== Problem == What is the product of <math> \frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\times\cdots\times\frac{2006}{2005} </math> ? <math> \textbf{(A)}\ 1\qquad\textbf{(B)}\...") |
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== Solution == | == Solution == | ||
By telescoping, it's easy to see the sum becomes <math> \frac{2006}{2}=\boxed{\textbf{(C)}\ 1003} </math>. | By telescoping, it's easy to see the sum becomes <math> \frac{2006}{2}=\boxed{\textbf{(C)}\ 1003} </math>. | ||
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| + | {{AMC8 box|year=2006|num-b=8|num-a=10}} | ||
Revision as of 15:57, 21 November 2011
Problem
What is the product of 
?
Solution
By telescoping, it's easy to see the sum becomes 
.
| 2006 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 8 |
Followed by Problem 10 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
