Difference between revisions of "2006 UNCO Math Contest II Problems/Problem 6"

(Created page with "== Problem == The sum of all of the positive integer divisors of <math>6^2=36</math> is <math>1+2+3+4+6+9+12+18+36=91</math> (a) Determine a nice closed formula (i.e. without ...")
 
(Solution)
Line 11: Line 11:
  
 
==Solution==
 
==Solution==
 +
{{solution}}
  
 
==See Also==
 
==See Also==

Revision as of 17:58, 9 December 2016

Problem

The sum of all of the positive integer divisors of $6^2=36$ is $1+2+3+4+6+9+12+18+36=91$

(a) Determine a nice closed formula (i.e. without dots or the summation symbol) for the sum of all positive divisors of $6^n$.

(b) Repeat for $12^n$.

(c) Generalize.

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.

See Also

2006 UNCO Math Contest II (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10
All UNCO Math Contest Problems and Solutions