2007 AMC 10A Problems/Problem 4

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Problem

The sum of four consecutive multiples of 5 is 110. What is the greatest of the four numbers?

Solution

Let the two consecutive odd integers be $a$, $a+2$. Then $a+2 = 3a$, so $a = 1$ and their sum is $4\ \mathrm{(A)}$.

See also

2007 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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