Difference between revisions of "2007 AMC 12B Problems/Problem 12"
Chickendude (talk | contribs) (New page - solution) |
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& = 840 - 9(83) \\ | & = 840 - 9(83) \\ | ||
& = 93 \Rightarrow \mathrm {(C)}</math> | & = 93 \Rightarrow \mathrm {(C)}</math> | ||
| + | |||
| + | ==See Also== | ||
| + | {{AMC12 box|year=2007|ab=B|num-b=11|num-a=13}} | ||
Revision as of 00:18, 22 February 2008
Problem 12
A teacher gave a test to a class in which $10%$ (Error compiling LaTeX. Unknown error_msg) of the students are juniors and $90%$ (Error compiling LaTeX. Unknown error_msg) are seniors. The average score on the test was 
. The juniors all received the same score, and the average score of the seniors was 
. What score did each of the juniors receive on the test?
Solution
Taking a weighted average
where x is the Juniors' score
$\begin{align*}x & = 10(84 - .9(83) \\ & = 840 - 9(83) \\ & = 93 \Rightarrow \mathrm {(C)}$ (Error compiling LaTeX. Unknown error_msg)
See Also
| 2007 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 11 |
Followed by Problem 13 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
