Difference between revisions of "2007 AMC 8 Problems/Problem 3"

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<math>\mathrm{(A)}\ 2 \qquad\mathrm{(B)}\ 5 \qquad\mathrm{(C)}\ 7 \qquad\mathrm{(D)}\ 10 \qquad\mathrm{(E)}\ 12</math>
 
<math>\mathrm{(A)}\ 2 \qquad\mathrm{(B)}\ 5 \qquad\mathrm{(C)}\ 7 \qquad\mathrm{(D)}\ 10 \qquad\mathrm{(E)}\ 12</math>
 
[[2007 AMC 8 Problems/Problem 3|Solution]]
 
  
 
== Solution ==
 
== Solution ==

Revision as of 15:52, 15 February 2010

Problem

What is the sum of the two smallest prime factors of $250$?

$\mathrm{(A)}\ 2 \qquad\mathrm{(B)}\ 5 \qquad\mathrm{(C)}\ 7 \qquad\mathrm{(D)}\ 10 \qquad\mathrm{(E)}\ 12$

Solution

We prime factor 250.

We get $2 * 5 * 5 * 5$

The two smallest are $2$ and $5$.

So, $2 + 5 = 7$

The answer is $\boxed{C}$