2007 AMC 8 Problems/Problem 3

Problem

What is the sum of the two smallest prime factors of $250$?

$\mathrm{(A)}\ 2 \qquad\mathrm{(B)}\ 5 \qquad\mathrm{(C)}\ 7 \qquad\mathrm{(D)}\ 10 \qquad\mathrm{(E)}\ 12$

Video Solution by OmegaLearn

https://youtu.be/7an5wU9Q5hk?t=272

Solution

The prime factorization of $250$ is $2 \cdot 5^3$. The smallest two are $2$ and $5$. $2+5 = \boxed{\text{(C) }7}$.

Video Solution by SpreadTheMathLove

https://www.youtube.com/watch?v=omFpSGMWhFc

See Also

2007 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
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All AJHSME/AMC 8 Problems and Solutions

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