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2007 AMC 8 Problems/Problem 3

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Problem

What is the sum of the two smallest prime factors of $250$ ?

$\mathrm{(A)}\ 2 \qquad\mathrm{(B)}\ 5 \qquad\mathrm{(C)}\ 7 \qquad\mathrm{(D)}\ 10 \qquad\mathrm{(E)}\ 12$

Solution

We prime factor 250.

We get $2 * 5 * 5 * 5$

The two smallest are $2$ and $5$ .

So, $2 + 5 = 7$

The answer is $\boxed{C}$

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