Difference between revisions of "2009 AMC 8 Problems/Problem 2"

 
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<math> \textbf{(A)}\ 7\qquad\textbf{(B)}\ 32\qquad\textbf{(C)}\ 35\qquad\textbf{(D)}\ 49\qquad\textbf{(E)}\ 112 </math>
 
<math> \textbf{(A)}\ 7\qquad\textbf{(B)}\ 32\qquad\textbf{(C)}\ 35\qquad\textbf{(D)}\ 49\qquad\textbf{(E)}\ 112 </math>
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==Solution==
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This means the ratio is <math>4:7</math>. If the ratio now is <math>28:x</math>, then that means <math>x= \boxed{\textbf{(D) }49}</math>.
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==Video Solution==
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https://youtu.be/USVVURBLaAc?t=59
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==Video Solution 2==
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https://youtu.be/kQfc1PFwbBE
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~savannahsolver
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2009|num-b=1|num-a=3}}
 
{{AMC8 box|year=2009|num-b=1|num-a=3}}
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{{MAA Notice}}

Latest revision as of 08:21, 30 May 2023

Problem

On average, for every 4 sports cars sold at the local dealership, 7 sedans are sold. The dealership predicts that it will sell 28 sports cars next month. How many sedans does it expect to sell?

$\textbf{(A)}\ 7\qquad\textbf{(B)}\ 32\qquad\textbf{(C)}\ 35\qquad\textbf{(D)}\ 49\qquad\textbf{(E)}\ 112$

Solution

This means the ratio is $4:7$. If the ratio now is $28:x$, then that means $x= \boxed{\textbf{(D) }49}$.

Video Solution

https://youtu.be/USVVURBLaAc?t=59

Video Solution 2

https://youtu.be/kQfc1PFwbBE

~savannahsolver

See Also

2009 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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