Difference between revisions of "2009 AMC 8 Problems/Problem 6"

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Steve's empty swimming pool will hold <math> 24,000</math> gallons of water when full. It will be filled by <math> 4</math> hoses, each of which supplies <math> 2.5</math> gallons of water per minute. How many hours will it take to fill Steve's pool?
 
Steve's empty swimming pool will hold <math> 24,000</math> gallons of water when full. It will be filled by <math> 4</math> hoses, each of which supplies <math> 2.5</math> gallons of water per minute. How many hours will it take to fill Steve's pool?
 
  
 
<math> \textbf{(A)}\  40  \qquad
 
<math> \textbf{(A)}\  40  \qquad
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\textbf{(D)}\  46  \qquad
 
\textbf{(D)}\  46  \qquad
 
\textbf{(E)}\  48</math>
 
\textbf{(E)}\  48</math>
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 +
==Solution==
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Each of the four hoses hose fills <math>24,000/4 = 6,000</math> gallons of water. At the rate it goes at it will take <math>6,000/2.5 = 2400</math> minutes, or <math>\boxed{\textbf{(A)}\ 40}</math> hours.
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2009|num-b=5|num-a=7}}
 
{{AMC8 box|year=2009|num-b=5|num-a=7}}

Revision as of 16:24, 25 December 2012

Problem

Steve's empty swimming pool will hold $24,000$ gallons of water when full. It will be filled by $4$ hoses, each of which supplies $2.5$ gallons of water per minute. How many hours will it take to fill Steve's pool?

$\textbf{(A)}\  40  \qquad \textbf{(B)}\   42  \qquad \textbf{(C)}\  44   \qquad \textbf{(D)}\  46   \qquad \textbf{(E)}\   48$

Solution

Each of the four hoses hose fills $24,000/4 = 6,000$ gallons of water. At the rate it goes at it will take $6,000/2.5 = 2400$ minutes, or $\boxed{\textbf{(A)}\ 40}$ hours.

See Also

2009 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions