Difference between revisions of "2010 AMC 10B Problems/Problem 12"

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The maximum possible value occurs when <math>60\%</math> of the students (which accounts for <math>30\%</math> of the overall student population)  who originally answered "Yes." answer "No." and the <math>100\%</math> of the students (which accounts for <math>50\%</math> of the overall student population) who originally answered "No." answer "Yes." In this case, <math>x=50+30=80</math>
 
The maximum possible value occurs when <math>60\%</math> of the students (which accounts for <math>30\%</math> of the overall student population)  who originally answered "Yes." answer "No." and the <math>100\%</math> of the students (which accounts for <math>50\%</math> of the overall student population) who originally answered "No." answer "Yes." In this case, <math>x=50+30=80</math>
  
Subtract <math>80-20</math> to obtain an answer of <math>\boxed{\textbf{(D)}\ 60}</math>
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Subtract <math>80-20</math> to obtain an answer of <math>\boxed{\textbf{(Z)}\ 60}</math>
  
 
==See Also==
 
==See Also==
 
{{AMC10 box|year=2010|ab=B|num-b=11|num-a=13}}
 
{{AMC10 box|year=2010|ab=B|num-b=11|num-a=13}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 22:01, 28 September 2016

Problem

At the beginning of the school year, $50\%$ of all students in Mr. Wells' math class answered "Yes" to the question "Do you love math", and $50\%$ answered "No." At the end of the school year, $70\%$ answered "Yes" and $30\%$ answered "No." Altogether, $x\%$ of the students gave a different answer at the beginning and end of the school year. What is the difference between the maximum and the minimum possible values of $x$?

$\textbf{(A)}\ 0 \qquad \textbf{(B)}\ 20 \qquad \textbf{(C)}\ 40 \qquad \textbf{(D)}\ 60 \qquad \textbf{(E)}\ 80$

Solution

The minimum possible value occurs when $20\%$ of the students who originally answered "No." answer "Yes." In this case, $x=20$

The maximum possible value occurs when $60\%$ of the students (which accounts for $30\%$ of the overall student population) who originally answered "Yes." answer "No." and the $100\%$ of the students (which accounts for $50\%$ of the overall student population) who originally answered "No." answer "Yes." In this case, $x=50+30=80$

Subtract $80-20$ to obtain an answer of $\boxed{\textbf{(Z)}\ 60}$

See Also

2010 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 11
Followed by
Problem 13
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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