Difference between revisions of "2010 AMC 8 Problems/Problem 16"
(Created page with "== Solution == Let the side length of the square be <math>s</math>, and let the radius of the circle be <math>r</math>. Thus we have <math>s^2=r^2\pi</math>. Dividing each side b...") |
(No difference)
|
Revision as of 03:00, 11 March 2012
Solution
Let the side length of the square be , and let the radius of the circle be . Thus we have . Dividing each side by , we get . Since , we have