Difference between revisions of "2011 UNCO Math Contest II Problems/Problem 9"

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(b) <math>T(N) = \binom{N-1}{3}-\binom{N-2}{3}+\binom{N-3}{3}-\binom{N-4}{3}+\cdots</math>
 
(b) <math>T(N) = \binom{N-1}{3}-\binom{N-2}{3}+\binom{N-3}{3}-\binom{N-4}{3}+\cdots</math>
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I found (a) <math>T(n) = T(n - 1) + 2(n-4)</math> and (b) <math>T(n) = 13 + n (n - 7).</math>
  
 
== See Also ==
 
== See Also ==

Revision as of 22:57, 6 November 2022

Problem

Let $T(n)$ be the number of ways of selecting three distinct numbers from $\left\{1, 2, 3,\cdots ,n\right\}$ so that they are the lengths of the sides of a triangle. As an example, $T(5) = 3$; the only possibilities are $\{2-3-4\},\{ 2-4-5\}$, and $\{3-4-5\}$.

(a) Determine a recursion for T(n).

(b) Determine a closed formula for T(n).


Solution

(a) $T(n+1)+T(n)=\binom{n}{3}$

(b) $T(N) = \binom{N-1}{3}-\binom{N-2}{3}+\binom{N-3}{3}-\binom{N-4}{3}+\cdots$

I found (a) $T(n) = T(n - 1) + 2(n-4)$ and (b) $T(n) = 13 + n (n - 7).$

See Also

2011 UNCO Math Contest II (ProblemsAnswer KeyResources)
Preceded by
Problem 8
Followed by
Problem 10
1 2 3 4 5 6 7 8 9 10
All UNCO Math Contest Problems and Solutions