2012 AMC 12B Problems/Problem 10

Revision as of 21:39, 23 February 2012 by Mbt123 (talk | contribs) (Created page with "==Problem== What is the area of the polygon whose vertices are the points of intersection of the curves x^2 + y^2 =25 and (x-4)^2 + 9y^2 = 81. ==Solution== The first curve i...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem

What is the area of the polygon whose vertices are the points of intersection of the curves x^2 + y^2 =25 and (x-4)^2 + 9y^2 = 81.


Solution

The first curve is a circle with radius 5 centered at the origin, and the second curve is an ellipse with center (4,0) and end points of (-5,0) and (13,0). Finding points of intersection, we get (-5,0) (4,3) and (4,-3), forming a triangle with height of 9 and base of 6. So 9x6x0.5 =27 ; B.