2013 AMC 8 Problems/Problem 14
Problem
Abe holds 1 green and 1 red jelly bean in his hand. Bob holds 1 green, 1 yellow, and 2 red jelly beans in his hand. Each randomly picks a jelly bean to show the other. What is the probability that the colors match?
Solution
The favorable responses are either they both show a green bean or they both show a red bean. The probability that both show a green bean is . The probability that both show a red bean is . Therefore the probability is
Solution 2
We can list out all the combinations and we get this: . There is a total of 8 combinations and 3 that are the same. Hence, we yield the answer .
Video Solution
https://youtu.be/NMpVIy8QxSY ~savannahsolver
See Also
2013 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
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