Difference between revisions of "2015 AMC 10B Problems/Problem 5"

(Created page with "==Problem== David, Hikmet, Jack, Marta, Rand, and Todd were in a <math>12</math>-person race with <math>6</math> other people. Rand finished <math>6</math> places ahead of Hik...")
 
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==Solution==
 
==Solution==
Because Marta was <math>6</math>th, Jack was <math>5</math>th, so Todd was <math>3</math>rd. Thus, Rand was <math>2</math>nd and the 8th place finisher was $\boxed{\mathbf{(B)}\ \mathrm{Hikmet}}
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Because Marta was <math>6</math>th, Jack was <math>5</math>th, so Todd was <math>3</math>rd. Thus, Rand was <math>2</math>nd and the 8th place finisher was <math>\boxed{\mathbf{(B)}\ \mathrm{Hikmet}}</math>
  
 
==See Also==
 
==See Also==
 
{{AMC10 box|year=2015|ab=B|num-b=4|num-a=6}}
 
{{AMC10 box|year=2015|ab=B|num-b=4|num-a=6}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 20:07, 4 March 2015

Problem

David, Hikmet, Jack, Marta, Rand, and Todd were in a $12$-person race with $6$ other people. Rand finished $6$ places ahead of Hikmet. Marta finished $1$ place behind Jack. David finished $2$ places behind Hikmet. Jack finished $2$ places behind Todd. Todd finished $1$ place behind Rand. Marta finished in $6$th place. Who finished in $8$th place?

$\textbf{(A) } \text{David} \qquad\textbf{(B) } \text{Hikmet} \qquad\textbf{(C) } \text{Jack} \qquad\textbf{(D) } \text{Rand} \qquad\textbf{(E) } \text{Todd}$

Solution

Because Marta was $6$th, Jack was $5$th, so Todd was $3$rd. Thus, Rand was $2$nd and the 8th place finisher was $\boxed{\mathbf{(B)}\ \mathrm{Hikmet}}$

See Also

2015 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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